Exam notes
Why the scheme works
Common-ion effect: Group II versus Group IV sulphides
H₂S ⇌ 2H⁺ + S²⁻. In dilute HCl the extra H⁺ pushes this equilibrium left, so [S²⁻] is very small and only sulphides with very low Ksp (CuS, PbS, HgS, CdS, Bi₂S₃, As₂S₃, SnS) exceed their solubility product. In ammoniacal solution OH⁻ removes H⁺, [S²⁻] rises, and the more soluble sulphides of Group IV (ZnS, MnS, NiS, CoS) precipitate.
Why NH₄Cl is added with NH₄OH in Group III
NH₄Cl supplies NH₄⁺, which suppresses the ionisation of NH₄OH (common-ion effect). [OH⁻] stays low, so only the least soluble hydroxides, Fe(OH)₃, Al(OH)₃ and Cr(OH)₃, precipitate. Without it, Zn²⁺, Mn²⁺, Ni²⁺, Co²⁺ and Mg²⁺ hydroxides could also come down. H₂S is boiled off first so that Group IV sulphides do not precipitate here, and conc. HNO₃ oxidises Fe²⁺ to Fe³⁺ because Fe(OH)₂ is too soluble to precipitate completely.
Why NH₄⁺ is tested on the original salt
Ammonium salts (NH₄Cl, NH₄OH, (NH₄)₂CO₃) are added as reagents during the group analysis, so a test for NH₄⁺ later on would always be positive. Warm the original salt with NaOH: NH₃ turns moist red litmus blue and gives dense white fumes with a glass rod dipped in conc. HCl.
Pb²⁺ appears in two groups
PbCl₂ is fairly soluble in cold water, so Pb²⁺ is not removed completely by dilute HCl. The remainder precipitates as black PbS in Group II. That is why lead is listed in both Group I and Group II.
Flame colours
| Na⁺ | persistent golden yellow |
| K⁺ | lilac (violet); view through blue cobalt glass to cut out sodium’s yellow |
| Ca²⁺ | brick red |
| Sr²⁺ | crimson red |
| Ba²⁺ | apple (grassy) green |
| Cu²⁺ | bluish green |