Suraj Sir Chemistry Classes
Coordination compounds · crystal field theory

Spectrochemical Series

Ligands ranked by the crystal-field splitting Δo they produce, from weak field (small Δ) to strong field (large Δ). Choose a metal ion and slide along the series to see the d-electrons rearrange, the spin state flip and the colour shift.

The order

Weak field to strong field

Tap a ligand to see why it sits where it does. It is also sent to the splitting lab below.

◄ weak field · small Δstrong field · large Δ ►
weak field (high spin with 3d ions)intermediate (depends on the metal)strong field (low spin with most 3d ions)

Splitting lab · octahedral complex

Build ML₆ and fill the d-orbitals

Strong-field ligands make Δo larger than the pairing energy P, so electrons pair up in t2g (low spin). Weak-field ligands leave Δo < P, so electrons spread out (high spin). Keys: ← → move along the series.

Metal ion
weak fieldstrong field

Diagram not to scale: the gap grows along the series and with metal charge. The dashed line marks where Δo equals P for this ion.

Colour

A complex shows the colour it does not absorb

A d–d transition absorbs light of energy Δo. The colour we see is the complementary colour, opposite on the wheel. As Δo grows, the absorption moves to shorter wavelength (towards blue and violet).

NCERT example
Adding ethane-1,2-diamine (en) step by step to Ni²⁺(aq)
Δo increases as H₂O is replaced by en
More complexes
Spin drill

High spin or low spin?

Real octahedral complexes from the syllabus. Count d-electrons, place the ligand in the series, then decide.

Score 0 / 0
Only d⁴–d⁷ octahedral ions have a choice between high and low spin.
Exam notes

Memory anchors and the reasons behind them

ClassLigands (NCERT order)Typical result with 3d ions
WeakI⁻ < Br⁻ < SCN⁻ < Cl⁻ < S²⁻ < F⁻ < OH⁻ < C₂O₄²⁻ < H₂OSmall Δo (Δo < P): high spin, more unpaired electrons. Exception: Co³⁺ is low spin even with H₂O and C₂O₄²⁻ (only F⁻ gives high-spin [CoF₆]³⁻).
IntermediateNCS⁻ < edta⁴⁻ < NH₃Depends on the metal and its charge: [Co(NH₃)₆]³⁺ is low spin, but [Co(NH₃)₆]²⁺ and [Fe(NH₃)₆]²⁺ are high spin.
Strongen < CN⁻ < CO (extended list adds bipy, phen, NO₂⁻ between en and CN⁻)Large Δo (Δo > P): low spin for most d⁴–d⁷ ions, e.g. [Fe(CN)₆]⁴⁻ (diamagnetic) and [Fe(CN)₆]³⁻ (one unpaired e⁻).
What else changes Δ (apart from the ligand)?
Oxidation state: higher charge on the metal gives a larger Δ (Co³⁺ > Co²⁺). Row of the metal: Δ rises down a group (3d < 4d < 5d), so 4d and 5d complexes are almost always low spin. Geometry: Δt ≈ (4/9) Δo, which is smaller than P, so tetrahedral complexes are high spin.
Why halides are weak and CO, CN⁻ are strong
Halides and OH⁻ are π-donors: their filled p orbitals push the t2g set up, shrinking Δ. NH₃ and en are σ-donors only. CO, CN⁻, NO₂⁻, bipy and phen are π-acceptors: their empty π* orbitals pull the t2g set down (back-bonding), widening Δ. The order cannot be predicted from ligand charge alone: neutral CO is the strongest and anionic I⁻ the weakest.
SCN⁻ and NCS⁻: same ion, two positions
Thiocyanate is ambidentate. Bonded through S (thiocyanato-S, written SCN⁻) it is weak field; bonded through N (thiocyanato-N, written NCS⁻) it sits just above H₂O. Similarly, NO₂⁻ bonded through N (nitro) is strong field, while ONO⁻ (nitrito-O) is weaker.
CFSE with pairing energy
CFSE = (−0.4 x + 0.6 y) Δo + mP, where x and y are the electrons in t2g and eg and m is the number of electron pairs formed in addition to those already present in the free ion. Example: low-spin d⁶ (t2g⁶) gives −2.4 Δo + 2P; high-spin d⁶ (t2g⁴ eg²) gives −0.4 Δo.
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